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Determinants


Let us consider an tex2html_wrap_inline7529matrix, the so-called matrix of order n
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Definition 2.3.1. Arbitrary ordering tex2html_wrap_inline7533 of indeces tex2html_wrap_inline7535 is called a permutation.

Definition 2.3.2. The ordering of two indeces in the permutation tex2html_wrap_inline7537 is called natural if the smaller index stands before the greatest one; in the opposite case, the greater index standing before the smaller one, it is said that the two indeces form an inversion.

Definition 2.3.3. A determinant is a law (mapping, function) that associates with each square matrix A a number, so-called determinant of the matrix
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where the summation goes over all the permutations tex2html_wrap_inline7541 of indeces tex2html_wrap_inline7543 and tex2html_wrap_inline7545 is the number of inversions in the permutation tex2html_wrap_inline7541 of the row indeces. We will use expressions: determinant of order n and its rows and cocumns.

Example 2.3.1. Let us consider the third order determinant
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Let us examine the last summand (-1)3a13a22a31. In the permutation 3 2 1 of the column indeces the index 3 forms with the index 2 and the index 1 an inversion. The index 2 does the same with the index 1. So the number of inversions tex2html_wrap_inline7545 in the permutation of the column indices is equal to 3.

Problem 2.3.1.* Which sign has the product
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of elements of determinant expression.

Properties of determinant

Example 2.3.2. Let us evaluate the determinant of order n, using the expansion by cofactors by the first column and then by the first row.
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or
 equation2450
Equation (1) is a linear homogeneous difference equation with constant coefficients which has the solution of type tex2html_wrap_inline7589 Let us try to find them:
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We are interested in non-trivial solution. So we have get a quadratic equation
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to find the solution of the difference equation (1). It has the solutions tex2html_wrap_inline7591, and so one of the solutions of equation (1) is Dn=(-1)n. As the number -1 is a double solution of the quadratic equation, Dn=(-1)nn will be a solution of the equation (1), too. Thus, we have got two linearly independent particular solutions of the linear homogeneous difference equation with constant coefficients. The general solution of the equation can be expressed in form
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From the conditions D1=-2 and D2=3 we can find the coefficients C1 and C2:
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So the given problem has the solution

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Problem 2.3.2.* Compute the determinant of order n
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Example 2.3.3. Evaluate the Vandermonde determinant
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We substract x1 times the penultimate row from the last row, then x1 times the (n-2)-th row from the penultimate row, then x1 times (n-3)-th row from the (n-2)-th row etc., in the end x1 times the second row from the first one. As a result, we get
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Using the expression by the first column and factoring out the common factors in the elements, we get
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Factoring out from the first columns the common factor x2-x1, from the second column tex2html_wrap_inline7627 tex2html_wrap_inline7629 , from the (n-1)-th column xn-x1, we get
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Using the same operations cycles, we shall result in

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Proposition 2.3.1 (The Laplace expansion theorem). It holds the so-called Laplace formula
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where the summation on the right goes over all determinants (minors) Mk of order k that can be formed of rows i1, i2, tex2html_wrap_inline7629 , ik and columns j1, j2, tex2html_wrap_inline7629 , jk, and An-k is the product of the number tex2html_wrap_inline7657 and the determinant of the matrix remaining from the matrix A by deleting the rows i1, i2, tex2html_wrap_inline7629 , ik and the columns j1, j2, tex2html_wrap_inline7629 , jk used ny forming the minor Mk.

Proof. See Kangro (1962, pp. 37-39). tex2html_wrap_inline5817

Example 2.3.4. Using the Laplace expansion by two first rows, transform the determinant
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As only three minors not equal to zero can be formed the two first rows, we get the expansion

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Problem 2.3.3.* Compute by the use of the Laplace formula the determinant
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By the Laplace expansion theorem, it holds for each matrix tex2html_wrap_inline7683 the equality
 
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Choosing tex2html_wrap_inline7685 we transform the determinant
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so that all the elements bij become zeros. To make tex2html_wrap_inline7689 into zeros we have to add to the (n+1)-th column b11 times the elements of the first column, b21 times the elements of the second column etc, and, in the end, bn1 times the elements of the n-th column. Next we make into zeros the elements tex2html_wrap_inline7701 For this we add to the (n+2)-th column b12 times the first column, b22 times the second column etc, and, in the end, bn2 times the n-th column etc. The last step will nullity the elements tex2html_wrap_inline7713 For this we add to the 2n-th column b1n times the first column, b2n times the second column etc, and, in the end, bnn times the n-th column. The result will be
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where
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Taking into account (2) and the fact that, by (3), tex2html_wrap_inline7725, we reach the assertion.

Proposition 2.3.1 (the theorem about the determinant of the product of matrices). For arbitrary matrices A and B of order n it holds
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